LaTeX 解答生成・検査パイプライン

実行日時: 2026-08-06T15:54:15（ID: 20260806-155415-bbbe0f） ← 履歴一覧に戻る

¥item 次の定積分を計算せよ。
  ¥begin{edaenumerate}
¥item $¥displaystyle ¥int_{0}^{¥frac{¥pi}{3}} ¥frac{1}{¥cos x} d x$ ¥vspace{23ZW}
¥item $¥displaystyle ¥int_{0}^{1} ¥frac{1}{¥sqrt{4-x^{2}}} d x$
¥item $¥displaystyle ¥int_{0}^{1} e^{x}¥left(e^{x}+1¥right)^{4} d x$ ¥vspace{23ZW}
¥item $¥displaystyle ¥int_{0}^{¥frac{¥pi}{4}} ¥tan ^{4} x¥left(1+¥tan ^{2} x¥right) d x$
¥item $¥displaystyle ¥int_{0}^{1} ¥frac{3 x-2}{e^{x}} d x$
¥item $¥displaystyle ¥int_{-1}^{¥sqrt{3}-2} ¥frac{1}{x^{2}+4 x+5} d x$

  ¥end{edaenumerate}

\item
  \begin{edaenumerate}
\item $\log(2+\sqrt{3})$
\item $\displaystyle \frac{\pi}{6}$
\item $\displaystyle \frac{(e+1)^5-32}{5}$
\item $\displaystyle \frac{1}{5}$
\item $\displaystyle 1-\frac{4}{e}$
\item $\displaystyle \frac{\pi}{12}$
  \end{edaenumerate}

誤りなし

\item
  \begin{edaenumerate}
\item $\log(2+\sqrt{3})$
\item $\displaystyle \frac{\pi}{6}$
\item $\displaystyle \frac{(e+1)^5-32}{5}$
\item $\displaystyle \frac{1}{5}$
\item $\displaystyle 1-\frac{4}{e}$
\item $\displaystyle \frac{\pi}{12}$
  \end{edaenumerate}